Air Canada AC4734 flight
Air Canada domestic flight AC4734 serves route Jacksonville to Newark. The flight departs six times per week (Monday, Tuesday, Wednesday, Friday, Saturday, and Sunday). Provided details are valid for the flight departing on 18th April, 2024.
Flight AC4734: Jacksonville - Newark
Departure
| Departure day | 18th April (Thursday) |
| Departure time | 18:05 (6:05 pm) |
| Departure terminal | N/A |
| Airport name | Jacksonville |
| Airport IATA code | JAX |
| City | Jacksonville |
| State / Province | FL |
| Country | United States |
Arrival
| Arrival day | 18th April (Thursday) |
| Arrival time | 20:40 (8:40 pm) |
| Arrival terminal | Terminal «C» |
| Airport name | Newark Liberty |
| Airport IATA code | EWR |
| City | Newark |
| State / Province | NJ |
| Country | United States |
General
| Flight number | AC4734 |
| Airline name | Air Canada |
| IATA carrier code | AC |
| Flight type | Domestic |
Operational
| Airplane type | E7W |
| Arrival day | Same day |
| Flight duration | 2h 35m |
| Distance | 1321 km / 820 mi. |
| Operated by | United Airlines flight UA3644 |
See also
All non-stop flights from Jacksonville to Newark Return flights (Newark to Jacksonville)Flight departure days
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