United Airlines UA731 flight
United Airlines domestic flight UA731 serves route Newark to Cleveland. The flight departs daily. Provided details are valid for the flight departing on 19th April, 2024.
Flight UA731: Newark - Cleveland
Departure
| Departure day | 19th April (Friday) |
| Departure time | 19:46 (7:46 pm) |
| Departure terminal | Terminal «C» |
| Airport name | Newark Liberty |
| Airport IATA code | EWR |
| City | Newark |
| State / Province | NJ |
| Country | United States |
Arrival
| Arrival day | 19th April (Friday) |
| Arrival time | 21:27 (9:27 pm) |
| Arrival terminal | N/A |
| Airport name | Cleveland-Hopkins |
| Airport IATA code | CLE |
| City | Cleveland |
| State / Province | OH |
| Country | United States |
General
| Flight number | UA731 |
| Airline name | United Airlines |
| IATA carrier code | UA |
| Flight type | Domestic |
Operational
| Airplane type | Boeing 737-700 |
| Arrival day | Same day |
| Flight duration | 1h 41m |
| Distance | 651 km / 404 mi. |
See also
All non-stop flights from Newark to Cleveland Return flights (Cleveland to Newark)Flight departure days
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