American Airlines AA4808 flight
American Airlines domestic flight AA4808 serves route Columbus to New York City. The flight departs daily. Provided details are valid for the flight departing on 5th May, 2024.
Flight AA4808: Columbus - New York City
Departure
| Departure day | 5th May (Sunday) |
| Departure time | 08:30 (8:30 am) |
| Departure terminal | N/A |
| Airport name | Port Columbus |
| Airport IATA code | CMH |
| City | Columbus |
| State / Province | OH |
| Country | United States |
Arrival
| Arrival day | 5th May (Sunday) |
| Arrival time | 10:29 (10:29 am) |
| Arrival terminal | Terminal «8» |
| Airport name | John F. Kennedy |
| Airport IATA code | JFK |
| City | New York City |
| State / Province | NY |
| Country | United States |
General
| Flight number | AA4808 |
| Airline name | American Airlines |
| IATA carrier code | AA |
| Flight type | Domestic |
Operational
| Airplane type | Embraer EMB 175 |
| Arrival day | Same day |
| Flight duration | 1h 59m |
| Distance | 778 km / 483 mi. |
See also
All non-stop flights from Columbus to New York City Return flights (New York City to Columbus)Flight departure days
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