Aeromexico AM4058 flight
Aeromexico domestic flight AM4058 serves route Newark to Atlanta. The flight departs five times per week (Monday, Tuesday, Wednesday, Friday, and Sunday). Provided details are valid for the flight departing on 21st April, 2021.
Flight AM4058: Newark - Atlanta
Departure
| Departure day | 21st April (Wednesday) |
| Departure time | 10:32 (10:32 am) |
| Departure terminal | Terminal «B» |
| Airport name | Newark Liberty |
| Airport IATA code | EWR |
| City | Newark |
| State / Province | NJ |
| Country | United States |
Arrival
| Arrival day | 21st April (Wednesday) |
| Arrival time | 13:12 (1:12 pm) |
| Arrival terminal | Terminal «S» |
| Airport name | Hartsfield-Jackson Atlanta |
| Airport IATA code | ATL |
| City | Atlanta |
| State / Province | GA |
| Country | United States |
General
| Flight number | AM4058 |
| Airline name | Aeromexico |
| IATA carrier code | AM |
| Flight type | Domestic |
Operational
| Airplane type | Boeing 737-800 |
| Arrival day | Same day |
| Flight duration | 2h 40m |
| Distance | 1201 km / 746 mi. |
| Operated by | Delta flight DL1618 |
See also
All non-stop flights from Newark to Atlanta Return flights (Atlanta to Newark)Flight departure days
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