Aeromexico AM4080 flight
Aeromexico domestic flight AM4080 serves route Atlanta to Cleveland. The flight departs approximately six times per week (Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday). Provided details are valid for the flight departing on 21st June, 2018.
Flight AM4080: Atlanta - Cleveland
Departure
| Departure day | 21st June (Thursday) |
| Departure time | 12:24 (12:24 pm) |
| Departure terminal | Terminal «S» |
| Airport name | Hartsfield-Jackson Atlanta |
| Airport IATA code | ATL |
| City | Atlanta |
| State / Province | GA |
| Country | United States |
Arrival
| Arrival day | 21st June (Thursday) |
| Arrival time | 14:13 (2:13 pm) |
| Arrival terminal | N/A |
| Airport name | Cleveland-Hopkins |
| Airport IATA code | CLE |
| City | Cleveland |
| State / Province | OH |
| Country | United States |
General
| Flight number | AM4080 |
| Airline name | Aeromexico |
| IATA carrier code | AM |
| Flight type | Domestic |
Operational
| Airplane type | McDonnell Douglas MD-90 |
| Arrival day | Same day |
| Flight duration | 1h 49m |
| Distance | 893 km / 554 mi. |
| Operated by | Delta flight DL2528 |
See also
All non-stop flights from Atlanta to Cleveland Return flights (Cleveland to Atlanta)Flight departure days
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