Aeromexico AM4108 flight
Aeromexico domestic flight AM4108 serves route Philadelphia to Atlanta. The flight departs daily. Provided details are valid for the flight departing on 17th May, 2025.
Flight AM4108: Philadelphia - Atlanta
Departure
| Departure day | 17th May (Saturday) |
| Departure time | 06:00 (6:00 am) |
| Departure terminal | Terminal «D» |
| Airport name | Philadelphia |
| Airport IATA code | PHL |
| City | Philadelphia |
| State / Province | PA |
| Country | United States |
Arrival
| Arrival day | 17th May (Saturday) |
| Arrival time | 08:10 (8:10 am) |
| Arrival terminal | N/A |
| Airport name | Hartsfield-Jackson |
| Airport IATA code | ATL |
| City | Atlanta |
| State / Province | GA |
| Country | United States |
General
| Flight number | AM4108 |
| Airline name | Aeromexico |
| IATA carrier code | AM |
| Flight type | Domestic |
Operational
| Airplane type | Airbus A321-100/200 |
| Arrival day | Same day |
| Flight duration | 2h 10m |
| Distance | 1073 km / 666 mi. |
| Operated by | Delta flight DL1269 |
See also
All non-stop flights from Philadelphia to Atlanta Return flights (Atlanta to Philadelphia)Flight departure days
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