Aeromexico AM4380 flight

Aeromexico domestic flight AM4380 serves route New York City to Atlanta. The flight departs daily. Provided details are valid for the flight departing on 10th April, 2023.

Flight AM4380: New York City - Atlanta

Departure
Departure day 10th April (Monday)
Departure time 18:00 (6:00 pm)
Departure terminal Terminal «4»
Airport name John F. Kennedy
Airport IATA code JFK
City New York City
State / Province NY
Country United States
Arrival
Arrival day 10th April (Monday)
Arrival time 20:47 (8:47 pm)
Arrival terminal Terminal «S»
Airport name Hartsfield-Jackson Atlanta
Airport IATA code ATL
City Atlanta
State / Province GA
Country United States
General
Flight number AM4380
Airline name Aeromexico
IATA carrier code AM
Flight type Domestic
Operational
Airplane type Boeing 757-200 (winglets)
Arrival day Same day
Flight duration 2h 47m
Distance 1224 km / 760 mi.
Operated by Delta flight DL1154

See also

All non-stop flights from New York City to Atlanta Return flights (Atlanta to New York City)

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