Aeromexico AM4468 flight

Aeromexico domestic flight AM4468 serves route New York City to Cleveland. The flight departs approximately six times per week (Monday, Wednesday, Thursday, Friday, Saturday, and Sunday). Provided details are valid for the flight departing on 5th January, 2022.

Flight AM4468: New York City - Cleveland

Departure
Departure day 5th January (Wednesday)
Departure time 14:55 (2:55 pm)
Departure terminal Terminal «4»
Airport name John F. Kennedy
Airport IATA code JFK
City New York City
State / Province NY
Country United States
Arrival
Arrival day 5th January (Wednesday)
Arrival time 16:45 (4:45 pm)
Arrival terminal N/A
Airport name Cleveland-Hopkins
Airport IATA code CLE
City Cleveland
State / Province OH
Country United States
General
Flight number AM4468
Airline name Aeromexico
IATA carrier code AM
Flight type Domestic
Operational
Airplane type Canadair CRJ 900
Arrival day Same day
Flight duration 1h 50m
Distance 685 km / 425 mi.
Operated by Delta flight DL4997

See also

All non-stop flights from New York City to Cleveland Return flights (Cleveland to New York City)

Flight departure days

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