WestJet WS6498 flight
WestJet domestic flight WS6498 serves route Cleveland to Atlanta. The flight departs daily. Provided details are valid for the flight departing on 10th May, 2024.
Flight WS6498: Cleveland - Atlanta
Departure
| Departure day | 10th May (Friday) |
| Departure time | 16:45 (4:45 pm) |
| Departure terminal | N/A |
| Airport name | Cleveland-Hopkins |
| Airport IATA code | CLE |
| City | Cleveland |
| State / Province | OH |
| Country | United States |
Arrival
| Arrival day | 10th May (Friday) |
| Arrival time | 18:39 (6:39 pm) |
| Arrival terminal | Terminal «S» |
| Airport name | Hartsfield-Jackson Atlanta |
| Airport IATA code | ATL |
| City | Atlanta |
| State / Province | GA |
| Country | United States |
General
| Flight number | WS6498 |
| Airline name | WestJet |
| IATA carrier code | WS |
| Flight type | Domestic |
Operational
| Airplane type | Airbus A321-100/200 |
| Arrival day | Same day |
| Flight duration | 1h 54m |
| Distance | 893 km / 555 mi. |
| Operated by | Delta flight DL2377 |
See also
All non-stop flights from Cleveland to Atlanta Return flights (Atlanta to Cleveland)Flight departure days
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